backAround

Problem:

Given a string, take the last char and return a new string with the last char added at the front and back, so "cat" yields "tcatt". The original string will be length 1 or more.

Test Cases:

backAround("cat") → "tcatt"
backAround("Hello") → "oHelloo"
backAround("a") → "aaa"

Solution:

public String backAround(String str) {
  return str.charAt(str.length()-1)+str+str.charAt(str.length()-1);
}